• Matéria: Matemática
  • Autor: frednadahgicheru
  • Perguntado 3 anos atrás

Given that 2x+3y/3x+4y=5 find the ratio y:x​

Respostas

respondido por: Alice17br
0

Reply:

x= 5-4y/2+4y,y≠-2

Step by step explanation:

2x+3xy/3xx+4=5

Multiply both sides (if you don't know how to do this, I'll explain it to you now!)

Multiply company members by 3

3(2x+3xy/3xx+4y)=3x5

Use the distributive property of multiplication and multiply each term inside the parentheses by 3

3x2x+3x3xy/3xx+3x4y=3x5

multiply the values

3x2x+3x3xy/3xx+3x4y=15

calculate a multiplication

6x+3x3xy/3xx+3x4y=15

Simplify numbers by dividing them by the greatest common factor 3

6x+3xy+3x4y=15

calculate a multiplication

62xy+1y=15 and that we multiply the members of the family x like this by 3)

6x+3yx+12y=15

Put the factor x in evidence in the expression

(6+3y)x+12y=15

Move the variables to the right member and change its sign (if not explain) this, I will explain it to you

Move the variable to the right member by adding or its opposite to both members

(6+3y)x+12y-12y=15-12y

Since the sum of two opposites is zero, removing them from the expression

(6+3y)x=15-12y (and this is how we move like variables to the right member and change the signs)

(6+3y)x=15-12y

Assume 6+3y≠0 and divide both query members by assume 6+3y

x=15-12y/6+3y,6+3y≠0

rewrite the constraint

x=15-12y/6+3y,y≠-2

Put the factor 3 in evidence in the expression

x=3(5-4y)/6+3y,y≠-2

x=3(5-4y)/3(2+y),y≠-2

Reduce the offer with 3

x=5-4y/2+y,y≠-2

and there we have the solution, hope it helped :>

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