Question

Uma moto percorrer 18.000 metros em 9 segundos .qual a sua velocidade no percurso?

Answer 1

Explicação:

t=9s

x=18000m

v=?

v=x/t

v=18000/9

v=2000m/s

Answer 2

$\Large\displaystyle\text{ \begin{gathered} \blue{\bf{ F\acute{o}rmula:}} \end{gathered} }$

$\Large\displaystyle\text{ \begin{gathered} \boxed{\boxed{\sf{ V_m=\frac{\Delta S}{\Delta t} }}}\end{gathered} }$

$\Large\displaystyle\text{ \begin{gathered} \blue{\bf{Dados: }} \end{gathered} }$

$\Large\displaystyle\begin{gathered} \begin{cases}\sf V_m=?\,m/s\\\sf \Delta S=18000\,m\\\sf\Delta t=9\,s\end{cases} \end{gathered}$

$\Large\displaystyle\text{ \begin{gathered} \blue{\bf{ Soluc_{\!\!,}\tilde{a}o:} }\end{gathered} }$

$\Large\displaystyle\text{ \begin{gathered} \sf{ V_m=\frac{18000\,m}{9\,s}} \end{gathered} }$

$\Large\displaystyle\text{ \begin{gathered} \therefore\red{\underline{\boxed{\boxed{\sf{V_m=2000\,m/s }}}}} \end{gathered} }$