Question

Questão 2 Determine a distância entre os pontos;

a) A (1, 3) e B (-2, 6)


b) A (-1,-2) e B (2,-4)

alguém me ajuda por favor :(​

Answer 1

Explicação passo-a-passo:

a) d(AB)=√[(1-(-2))^2+(3-6)^2]= 3√2

b) d(AB)=√[((-1)^2-((-2)-(-4))^2]= √13

Answer 2

$\Large\boxed{\begin{array}{l} \sf{a) \: d_{AB }=\sqrt{(x_{A} -x_{B})^{2}+(y_{A} -y_{B})^{2}}} \\ \sf d_{AB } = \sqrt{(1 - ( - 2)) {}^{2} + (3 - 6) {}^{2} } \\ \sf d_{AB } = \sqrt{3 {}^{2} + ( - 3) {}^{2} } \\ \sf{d_{AB } = \sqrt{9 + 9} } \\ \sf d_{AB } = \sqrt{18} \\ \huge\boxed{\boxed{\boxed{\boxed{\sf{d_{AB } = 3 \sqrt{2} }}}}} \checkmark\end{array}}$

$\Large\boxed{\begin{array}{l} \sf{b) \: d_{AB }=\sqrt{(x_{A} -x_{B})^{2}+(y_{A} -y_{B})^{2}}} \\ \sf{d_{AB } = \sqrt{(( - 1) - 2) {}^{2} + (( - 2) - ( - 4)) {}^{2} } } \\ \sf{d_{AB } = \sqrt{( - 3) {}^{2} + 2 {}^{2} } } \\\sf{d_{AB } = \sqrt{9 + 4} } \\ \huge \boxed{ \boxed{ \boxed{ \boxed{ \sf{\sf{d_{AB } } = \sqrt{13} }}}}} \checkmark\end{array}}$