Question

Determine, da decomposição em fatores primos o mdc de:
a) 48, 64 e 80
b) 48,72 e 96
c)18,27 e 36
ME AJUDEM POR FAVOR ​

Answer 1

$\large\boxed{\begin{array}{l}\sf m\cdot d\cdot c\,(48,64,80)=16\\\\\begin{array}{r|l}\sf48,64,80 & \sf2\\\sf24,32,40&\sf2\\\sf12,16,20&\sf2\\\sf6,8,10&\sf2\\\sf3,4,5&\overline{\sf2^4=16}\end{array}\end{array}}$

$\large\boxed{\begin{array}{l}\sf m\cdot d\cdot c\,(48,72,96)=24\\\\\begin{array}{r|l} \sf48,72,96& \sf2\\\sf24,36,48&\sf2\\\sf12,18,24&\sf2\\\sf6,9,13&\sf3\\\sf2,3,4&\overline{\sf2^3\cdot3=24}\end{array}\end{array}}$

$\large\boxed{\begin{array}{l}\sf m\cdot d\cdot c\,(18,27,36)=9\\\\\begin{array}{r|l} \sf18,27,36&\sf3\\\sf6,9,12&\sf3\\\sf2,3,4&\overline{\sf3^2=9} \end{array}\end{array}}$