• Matéria: Matemática
  • Autor: isabelaremafernandes
  • Perguntado 3 anos atrás

Medidas de ângulos
12° 25' 12" ×3
25° 16' 49" ×4
37° 44' 18" ×6

Valendo 100 pontos para quem me ajuda por favor preciso muito é pra ontem.

Respostas

respondido por: auditsys
2

Resposta:

\textsf{Leia abaixo}

Explicação passo a passo:

\mathsf{12^{\circ} \:25'\:12'' \times 3}

\mathsf{36^{\circ} \:75'\:36''}

\mathsf{36^{\circ} \:(60' + 15')\:36''}

\mathsf{36^{\circ} \:(1^{\circ}+ 15')\:36''}

\boxed{\boxed{\mathsf{37^{\circ} \:15'\:36''}}}

\mathsf{25^{\circ} \:16'\:49'' \times 4}

\mathsf{100^{\circ} \:64'\:196''}

\mathsf{100^{\circ} \:64'\:(180'' + 16'')}

\mathsf{100^{\circ} \:64'\:(3' + 16'')}

\mathsf{100^{\circ} \:67'\:16''}

\mathsf{100\º\:(60' + 7')\:16''}

\mathsf{100^{\circ} \:(1^{\circ}  + 7')\:16''}

\boxed{\boxed{\mathsf{101^{\circ} \:7'\:16''}}}

\mathsf{37^{\circ} \:44'\:18'' \times 6}

\mathsf{222^{\circ} \:264'\:108''}

\mathsf{222^{\circ} \:264'\:(60'' + 48'')}

\mathsf{222^{\circ} \:264'\:(1' + 48'')}

\mathsf{222^{\circ} \:265'\:48''}

\mathsf{222^{\circ} \:(240' + 25')\:48''}

\mathsf{222^{\circ} \:(4^{\circ}  + 25')\:48''}

\boxed{\boxed{\mathsf{226^{\circ} \:25'\:48''}}}


isabelaremafernandes: OBRIGADA MOÇO TE AMO
Perguntas similares