• Matéria: Matemática
  • Autor: avilamatheus444
  • Perguntado 3 anos atrás

clasifique como v ou f

A)2⁷.2²=2⁹
B)(7³)²=7⁵
C)(2³)²=2⁶
D) A D TA NA IMAGEM ​

Anexos:

Respostas

respondido por: CyberKirito
0

\Large\boxed{\begin{array}{l}\underline{\rm Propriedades\,das\,pot\hat encias}\\\sf \,I~a^m\cdot a^n=a^{m+n}\\\sf II~\dfrac{a^m}{a^n}=a^{m-n}\\\\\sf III~(a^m)^n=a^{m\cdot n}\\\\\sf IV~(a\cdot b)^n=a^n\cdot b^n\\\sf V~\bigg(\dfrac{a}{b}\bigg)^n=\dfrac{a^n}{b^n},com\,b\ne0\end{array}}

\large\boxed{\begin{array}{l}\rm Classifique\,como\,V\,ou\,F\\\rm A)~2^7\cdot2^2=2^9\\\rm B)~(7^3)^2=7^5\\\rm C)(2^3)^2=2^6\\\rm D)\dfrac{10^3}{10^5}=10^{-3}\end{array}}

\Large\boxed{\begin{array}{l}\underline{\bf Soluc_{\!\!,}\tilde ao\!:}\\\sf A)~2^7\cdot2^2=2^{7+2}=2^9\longrightarrow V\\\sf B)(7^3)^2=7^{3\cdot2}=7^6\ne7^5\longrightarrow F\\\sf C)(2^3)^2=2^{3\cdot2}=2^6\longrightarrow V\\\sf D)\dfrac{10^3}{10^5}=10^{3-5}=10^{-2}\ne10^{-3}\longrightarrow F\end{array}}

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