Question

O valor 25-[12-(3×2+1)]=??? é:

Answer 1

Resposta: 20

Explicação passo a passo:

25-[12-(3×2+1)]= (primeiro resolve a multiplicação e os parênteses))

25-[12-(6+1)]=

25-[12-(7)]=

25-[12-7]=

25-[5]=

25 - 5 = 20

Espero ter ajudado.

Answer 2

$\boxed{\begin{array}{l} \sf Em\,uma\,express\tilde{a}o\,num\acute{e}rica\,resolvemos:\\\sf1^a\, pot\hat{e}ncias\,e\,ra\acute{i}zes\, na\, ordem\, que \,vier\\\sf 2^a\, multiplicac_{\!\!,}\tilde{a}o \,e \,divis\tilde{a}o \,na\, ordem \,que \,vier\\\sf 3^a\,adic_{\!\!,}\tilde{a}o\, e \,subtrac_{\!\!,}\tilde{a}o\, na\, ordem\, que\, vier.\\\sf Al\acute{e}m\,disso\, eliminar-se:\\\sf 1^\circ\,\bigg(~\bigg)\rightarrow par\hat{e}nteses\\\\\sf 2^\circ\,\bigg[~\bigg]\rightarrow colchetes\\\\\sf 3^\circ\,\bigg\{~\bigg\}\rightarrow chaves\end{array}}$

$\Large\boxed{\begin{array}{l}\sf25-[12-(3\cdot2+1)]\\\sf resolvendo\,os\, par\hat{e}nteses:\\\sf25-[12-(6+1)]\\\sf25-[12-7]\\\sf resolvendo\,os\, colchetes:\\\sf 25-[5]\\\sf25-5\\\sf20\blue\checkmark\end{array}}$