Question

resolva equação de 2 grau

x²+5X=0


x²-49=0
​

Answer 1

x²+5x=0 Resposta: x²=-5

Explicação passo a passo:

1. Determine the quadratic equation’s coefficients a, b and c

Use the standard form,(ax²+bx+c=0)  , to find the coefficients of our equation,

x²+5x+0=0:

a=1

b=5

c=0

2. Plug these coefficients into the quadratic formula

The quadratic formula gives us the roots for ax²+bx+c=0 , in which a, b  and c are numbers (or coefficients), as follows:

x=(-b±sqrt(b^2-4ac))/(2a)

x=(-5±sqrt(25))/(2)

to get the result:

x=(-5±sqrt(25))/2

3. Simplify square root sqrt(25)

Simplify 25 by finding its prime factors:

The prime factorization of 25 is 5²

Write the prime factors:

sqrt(25)=sqrt(5*5)

Group the prime factors into pairs and rewrite them in exponent form:

sqrt(5*5)=sqrt(5^2)

Use the rule sqrt(x^2)=x to simplify further:

sqrt(5^2)=5

4. Solve the equation for x

x=(-5±5)/2

The ± means two answers are possible.

Separate the equations:

x_1=(-5+5)/2 and x_2=(-5-5)/2

x_1=(-5+5)/2

x_1=(-0)/2

x_1=-0

x_2=(-5-5)/2

x_2=(-10)/2

(Result final) x_2=-5

Desculpe não fazer a outra equação porque demora para calcular