• Matéria: Matemática
  • Autor: joaozinho1510
  • Perguntado 9 anos atrás

Resolvendo a integral:

Anexos:

Lukyo: Esta integral dá zero!!
Lukyo: Estou seguro de que é zero...

Respostas

respondido por: Lukyo
1
Resolvendo a integral pelo Teorema de Fubini (integrais iteradas):

\displaystyle\int_0^{\pi}\int_0^1{r\cos\theta\,dr\,d\theta}\\\\\\ =\int_0^{\pi}\int_0^1{\cos\theta\cdot r\,dr\,d\theta}\\\\\\ =\int_0^{\pi}{\cos\theta\cdot \left.\left(\dfrac{r^2}{2} \right )\right|_0^1\,d\theta}\\\\\\ =\int_0^{\pi}{\cos\theta\cdot \left(\dfrac{1^2}{2}-\dfrac{0^2}{2} \right )\,d\theta}\\\\\\ =\int_0^{\pi}{\dfrac{1}{2}\,\cos\theta\,d\theta}

=\left.\left(\dfrac{1}{2}\,\mathrm{sen\,}\theta\right)\right|_0^{\pi}\\\\\\ =\dfrac{1}{2}\,\mathrm{sen\,}\pi-\dfrac{1}{2}\,\mathrm{sen\,}0\\\\\\ =0.

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