Question

ache as raizes de: n²-n+42

Answer 1

N² + N -42 = 0 
∆ = b² -4ac 
∆ = (1)² -4.(1).(-42) 
∆ = 1 + 168 
∆ = 169 
N = (-b +- raiz de ∆)/2 
N = (-1 +- 13)/2 
N1 = (-1 -13)/2 = -14/2 = -7 
N2 = (-1 + 13)/2 = 12/2=6
 N1 = -7 e N2 = 6