Question

Calcule a soma dos seis primeiros termos da Pg (1/3 , 1/6 , 1/12 , ...)

Answer 1

Olá Misael

PG

u1 = 1/3
u2 = 1/6
u3 = 1/12

razão

q = u2/u1 = (1/6)/(1/3) = 1/2

formula da soma

Sn = u1*(1 - q^n)/(1 - q)

S6 = (1/3)*(1 - (1/2)^6)/(1 - 1/2)

S6 = (1/3)*(1 - 1/64)/(1/2)

S6 = (2/3)*(64 - 1)/64 = 21/32 

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