Question

Alguém me ajuda nessa tarefa pls, é pra agr...

Answer 1

Resposta:

$a)-6+5+12-7=4\\b)\left(10\right)-\left(8\right)-\left(-18\right)+\left(-6\right)=14\\c)\left(-1\right)+\left(-7\right)\div \left(-7\right)=0\\d)\left(-6\right)^2+\left(-3\right)=33\\e)\left(-2\right)+\left(-2\right)\div \left(-2\right)=-1\\f)\left(-1\right)-\left(6\right)\left(4\right)-\left(3\right)=-28\\g)-5\left(4-12\div \:2\right)=10\\h)\left(-4\right)^2+\sqrt{9}\cdot \left(-2\right)=10$