Question

A 3×2-5×+1=0
c 4x2-×=0​

Answer 1

A) 3×^2-5×+1=0
a = 3; b = - 5; c = 1
/\= b^2 - 4ac
/\= (-5)^2 - 4.3.1
/\ = 25 - 12
/\= 13

X = (- b +/- \/ /\)/2a
X = [-(-5) +/- \/13]/2.3
x = (5 +/- \/13)/6

R.:
X' = (5+ \/13)/6
X " = (5 - \/13)/6

_________

c)
4x^2-×=0​
X.(4x-1)= 0
x = 0
4x - 1 = 0
4x = 1
x = 1/4

R.:
S = {0, 1/4}