• Matéria: Matemática
  • Autor: dudabatistaalvess
  • Perguntado 3 anos atrás

2x elevado a 4 -x elevado a 2+1=0

Respostas

respondido por: cavalcantidnl
1

Resposta:

2x^4-x^2+1=0

2u^2-u+1=0

u=\frac{1}{4}+i\frac{\sqrt{7}}{4},\:u=\frac{1}{4}-i\frac{\sqrt{7}}{4}

x=\frac{\left(4\sqrt{7}+\sqrt{14}\right)\sqrt{2\sqrt{2}-1}}{28}+\frac{\sqrt{2}\sqrt{2\sqrt{2}-1}}{4}i,\:x=-\frac{\left(4\sqrt{7}+\sqrt{14}\right)\sqrt{2\sqrt{2}-1}}{28}-\frac{\sqrt{2}\sqrt{2\sqrt{2}-1}}{4}i,\:x=-\frac{\left(4\sqrt{7}+\sqrt{14}\right)\sqrt{2\sqrt{2}-1}}{28}+\frac{\sqrt{2}\sqrt{2\sqrt{2}-1}}{4}i,\:x=\frac{\left(4\sqrt{7}+\sqrt{14}\right)\sqrt{2\sqrt{2}-1}}{28}-\frac{\sqrt{2}\sqrt{2\sqrt{2}-1}}{4}i

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