Question

Considerando log 2 = 0,3 e log 3 = 0,5 , podemos afirmar que log 36 vale

Answer 1

$\log36=$

$\log(2^2\cdot 3^2)=$

$\log2^2+\log3^2=$

$2\log2+2\log3=$

$2(\log2+\log3)=$

$2(0,3+0,5)=$

$2\cdot 0,8=$

$1,6$