Question

5) Aplique as propriedades e calcule as seguintes potências:

a)10-² =

b)(5/8)-²

c)(2³)² =

d)(3/2)-3=

e) (-3)-³ =

f)(1/2)-⁵ =

g)(-3/9)-² =

h)2⁰ =

i)3¹ =

j)-(-2)⁴ =

k)(3.2)² =

l)(4.5)³ =​

Answer 1

Explicação passo-a-passo:

a) 10-²= (1/10)²= 1/100

b) (5/8)-²= (8/5)²= 64/25

c) 2³×²= 2⁶= 64

d) (3/2)-³= (2/3)³= 8/27

e) (-3)-³= (- 1/3)³= - 1/27

f) (1/2)-⁵= (2/1)⁵= 2⁵= 32

g) (-3/9)-²= (-9/3)²= + 81/9

h) 2⁰= 1

i) 3¹= 3

j) - ( - 2)⁴= - (+16)= - 16

k) 3².2²= 9.4= 36

l) 4³.5³= 64 . 125=8000

Answer 2

Explicação passo-a-passo:

$a)10 {}^{ - 2} = ( \frac{1}{10} ) {}^{2} = \frac{1}{100}$

$b)( \frac{5}{8} ) {}^{ - 2} = ( \frac{8}{5} ) {}^{2} = \frac{64}{25}$

$c)(2 {}^{3} ) {}^{2} = 2 {}^{3.2} = 2 {}^{6} = 64$

$d)( \frac{3}{2} ) {}^{ - 3} = ( \frac{2}{3} ) {}^{3} = \frac{8}{27}$

$f)( \frac{1}{2} ) {}^{ - 5} = 2 {}^{5} = 32$

$g)( \frac{ - 3}{9} ) {}^{ - 2} = ( \frac{ - 9}{3} ) {}^{2} = ( - 3) {}^{2} = 9$

$h)2 {}^{0} = 1$

$i)3 {}^{1} = 3$

$j) - ( - 2) {}^{4} = - 16$

[tex]k)(3.2) {}^{2} = 6²=36

[tex]l)(4.5) {}^{3} = 20³=8.000