Question

preciso com cálculos me ajudem!!!!!!!!​

Answer 1

$> resolucao \\ \\ \geqslant teorema \: de \: tales \\ \\ \\ a \: ) \: x = 48 \: \: e \: \: y = 22 \\ \\ \\ > \frac{24}{60} = \frac{y}{55} \\ \\ > 60y = 24 \times 55 \\ \\ 60y = 1320 \\ \\ y = \frac{1320}{60} \\ \\ y = 22 \\ \\ \\ \\ > \frac{60}{x} = \frac{55}{44} \\ \\ 55x = 44 \times 60 \\ \\ 55x = 2640 \\ \\ x = \frac{2640}{55} \\ \\ x = 48 \\ \\ = = = = = = = = = = = = = = = = = = \\ \\ \\ b \: ) \: \: x = 35 \: \: e \: \: y = 54 \\ \\ \\ > \frac{40}{x} = \frac{48}{42} \\ \\ > 48x = 40 \times 42 \\ \\ 48x = 1680 \\ \\ x = \frac{1680}{48} \\ \\ x = 35 \\ \\ \\ > \frac{35}{45} = \frac{42}{y} \\ \\ > 35y = 42 \times 45 \\ \\ 35y = 1890 \\ \\ y = \frac{1890}{35} \\ \\ y = 54 \\ \\ \\ > < > < > < > < > < > < > >$