Question

se A=(1+ a)², B=(1+a)×(1–a) e C=(2a–1)² determine A–B+C

Answer 1

6a²-2a+1

A = (1+a)² = (1)²+2(1)(a)+(a)² = 1+2a+a²

B = (1+a)(1-a) = 1-a+a-a² = 1-a²

C = (2a-1)² = (2a)²-2(2a)(1)(+1)² = 4a²-4a+1

A-B+C

(1+2a+a²)-(1-a²)+(4a²-4a+1)

1+2a+a²-1+a²+4a²-4a+1

6a²-2a+1

❤️❤️ Ótimo dia ❤️❤️

06/05/22