Question

sen630º - 8.cos900º + 3.tg 405º

Answer 1

$\sin(630) - 8 \cos(900) + 3 \tan(405) \\ 0 - 8 \: . \: ( - 1) + 3 \: . \: 1 \\ 8 + 3 \\ \boxed{\boxed{\boxed{11}}}$

att. yrz