Question

Simplifique: $\sqrt{( 3^{4}) ^{-3}^/ ^{2} }$ por favor me ajudem urgente

Answer 1

Olá, Zanardereginata.

$\sqrt{( 3^{4}) ^{-\frac{3}{2} }}=\sqrt{3^{4\cdot(-\frac{3}{2})}}=\sqrt{3^{2\cdot(-3) }}=\sqrt{3^{-6}}=3^{\frac{-6}{2}}=3^{-3}=\frac1{3^3}=\frac1{27}$