Question

descubra o valor da expressão

Answer 1

Resposta:

$\textsf{Leia abaixo}$

Explicação passo a passo:

$\begin{cases}\mathsf{x + y = \dfrac{15}{7}}\\\\\mathsf{x - y = \dfrac{1}{14}}\end{cases}$

$\mathsf{E = \dfrac{\dfrac{(x^2 + 2xy + y^2)(x^3- y^3)}{(x^2 - y^2)(x^2 + xy + y^2)}}{\dfrac{(x^2 - xy)}{2x}}}$

$\mathsf{E = \dfrac{\dfrac{(x + y)^2(x - y)(x^2 + xy + y^2)}{(x - y)(x + y)(x^2 + xy + y^2)}}{\dfrac{(x^2 - xy)}{2x}}}$

$\mathsf{E = \dfrac{\dfrac{(x + y)^2}{(x + y)}}{\dfrac{x(x - y)}{2x}}}$

$\mathsf{E = \dfrac{(x + y)}{\dfrac{x(x - y)}{2x}}}$

$\mathsf{E = (x + y)\:.\:\dfrac{2x}{x(x - y)}}$

$\mathsf{E = 2\:.\:\dfrac{(x + y)}{(x - y)}}$

$\mathsf{E = 2\:.\:\dfrac{15}{7}\:.\:\dfrac{14}{1}}$

$\boxed{\boxed{\mathsf{E = 60}}}$