Question

alguem me ajuda a resolver??​

Answer 1

Resposta:

a) x = ± 7

b) x = ± 1

c) x = ± 5

d) x = ± 1

e) x = 3 / x = 2

f) x = -6 / x = -2

Explicação passo a passo:

a) x² - 49 = 0

x² = +49

x = √49

x = ± 7

b) x² -1 = 0

x² = 1

x = ± 1

c) 2x² - 50 = 0

2x² = 50

x² = 50 / 2

x² = 25

x = √25

x = ± 5

d) 7x² - 7 = 0

7x² = 7

x² = 7 / 7

x² = 1

x = √1

x = ±1

e) x² - 5x + 6 = 0

usando Baskhara x = (- b ± √b²-4×a×c)/(2×a)

e sabendo que a=1 ; b=-5 c=-6

x = -(-5) ± √ [(-5)² - 4×1×6] / 2×1

x = 5 ± √ 25 - 24 / 1

x = (5 ± 1) / 2

x' = (5 + 1) / 2  =>  x' = 6/2  =>  x' = 3

x'' = (5 - 1) / 2  =>  x'' = 4/2  =>  x'' = 2

f) x² + 8x + 12 = 0

usando Baskhara x = (- b ± √b²-4×a×c)/(2×a)

e sabendo que a=1 ; b=8 c=12

x = -(8) ± √ [(8)² - 4×1×12] / 2×1

x = -8 ± √ (64 - 48) / 2

x = -8 ± √ 16 / 2

x = -8 ± 4 / 2

x' = (-8 + 4) / 2  =>  x' = -4 / 2  =>  x' = -2

x'' = (-8 - 4) / 2  =>  x'' = -12 / 2  =>  x'' = -6