Question

Resolva:
25-( 34²¹+21³-7x10) +300-4000+200²¹

Answer 1

Resposta:

25−(3421+213−(7)(10))+300−4000+20021

=25−(1.4489628738953409e+32+213−(7)(10))+300−4000+20021

=25−(1.4489628738953409e+32+9261−(7)(10))+300−4000+20021

=25−(1.4489628738953409e+32−(7)(10))+300−4000+20021

=25−(1.4489628738953409e+32−70)+300−4000+20021

=25−1.4489628738953409e+32+300−4000+20021

=−1.4489628738953409e+32+300−4000+20021

=−1.4489628738953409e+32−4000+20021

=−1.4489628738953409e+32+20021

=−1.4489628738953409e+32+2.0971519999999998e+48

=2.0971519999999998e+48

Explicação passo a passo: