Question

-4 X elevado a 2 + 8x - 4 = 0​

Answer 1

Resposta:

$-4x^{2} +8x-4=0$

coeficientes: a = -4, b = 8, c = -4

$x=\frac{-b+-\sqrt{b^{2}-4.a.c } }{2.a} \\ \\ x=\frac{-8+-\sqrt{8^{2}-4.(-4).(-4) } }{2.(-4)} \\ \\ x=\frac{-8+-\sqrt{64-64} }{-8} \\ \\ x=\frac{-8+-\sqrt{0} }{-8} \\ \\ x=\frac{-8}{-8} =+1\\ \\ \\ x=1$