Question

Dada f(x)=2x²+5x-3 determine

Answer 1

Resposta:

$f(-2)=-5\\f(-1)=-6\\f(0)=-3\\f(3)=30\\f(h+1)=2h^2+9h+4$

Explicação passo a passo:

Considerando a função: $f(x)=2x^{2}+5x-3$

$f(-2)=2.(-2)^{2} +5(-2)-3=2.4-10-3=8-13=-5\\\\f(-1)=2.(-1)^{2} +5(-1)-3=2-5-3=-6\\\\f(0)=2.(0)^{2} +5(0)-3=-3\\\\f(3)=2.(3)^{2} +5(3)-3=2.9+15-3=30\\\\f(h+1)=2.(h+1)^{2} +5(h+1)-3=2.(h^{2} + 2h +1)+5h+5-3=\\2h^{2}+4h+2+5h+2=2h^2+9h+4$