Question

Resolva,em R,as equações trigonométricas
Sen(x-pi/3)=raiz de 3/2
Me ajudeeeeemmmmmm

Answer 1

Resposta:

$sen(x-\frac{\pi }{3})=\frac{\sqrt{3} }{2} \\\\sen(x-\frac{\pi }{3})=sen \frac{\pi }{3} \\\\x-\frac{\pi }{3} =\frac{\pi }{3}+2k\pi \implies x=\frac{\pi }{3}+\frac{\pi }{3} +2k\pi \\\\x=\frac{2\pi }{3} +2k\pi ,~k\in~Z\\ou\\x-\frac{\pi }{3} =\pi -\frac{\pi }{3} +2k\pi \implies x=\pi +\frac{\pi }{3}-\frac{\pi }{3} +2k\pi \\\\x= \pi +2k\pi ,~k\in Z$