Question

9x²-6+1=0 formula de Bhaskara

Answer 1

Δ=  b² – 4ac

Bhaskara = x = – b ± √Δ / 2a

Assim encontramos Δ= (-6)² - 4. 9.1

Δ= 36 - 36

Δ= 0

Partindo para bhaskara =  x = – b ± √Δ / 2a

x = -(-6) ±√0/2.9

x¹ = 36+0/ 18

x¹ = 2

x² = 36-0/18

x² = 2

Desse modo x¹=x²=2