• Matéria: Matemática
  • Autor: erickkzanfir
  • Perguntado 3 anos atrás

A) {50-[2+4²(12)5]} alguém me ajuda

Respostas

respondido por: silvakayk035
0

a) 7-(1+3) = 7-4 = 3

b) 9-(5-1+2) = 9-6 = 3

c)10-(2+5)+4 = 10-7+4 = 7

d)(13-7)+8-1 = 6+8-1 = 13

e)15-(3+2)-6 = 15-5-6 = 4

f) (10-4)-(9-8)+3 = 6-1+3 = 8

g)50-[37-(15-8)} = 50-[37-7] = 50-30 = 20

h)28+[50-(24-2)-10 = 28+[50-22-10] = 28+18 = 46

i)20+[13+(10-6)+4} = 20+[13+4+4] = 20+21 = 41

j)52-{12+[15-(8-4)]} = 52-{12+[15-4]} = 42-{12+11} = 42-23 = 19

k)25+{12+[2-(8-6)+2]}= 25+{12+[2-2+2]} = 25+{12+2} = 25+14 = 39

l){[(18-3)+(7+5)-2]+5}-12 = {[15+12-2]+5}-12 = {25+5}-12 = 30-12 = 18

m)65-{30-[20-(10-1+6)+1]} = 65-{30-[20-15+1]]} = 65-{30-6} = 65-36 = 29

n)45+{15-[(10-8)+(7-4)-3]-4} = 45+{15-[2+3-3]-4} = 45+{11-2} = 45+9 = 54

o)40+{50-[35-(25+5)-1]}+7 = 40+{50-[35-39-1]} = 40+{50+5} = 40+55 = 95

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