Question

aplique o Teorema de Pitágoras e determine X em cada delta

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Answer 1

$> resolucao \\ \\ \geqslant teorema \: \: de \: \: pitagoras \\ \\ {x}^{2} + b {}^{2} = a {}^{2} \\ {x}^{2} + 24 {}^{2} = 25 {}^{2} \\ x {}^{2} + 576 = 625 \\ {x}^{2} = 625 - 576 \\ {x}^{2} = 49 \\ x = \sqrt{49} \\ x = 7 \\ \\ \\ \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant$