Question

Determinar o 12 termo da p.g(216,72,24..)

Answer 1

Explicação passo a passo:

PG (216, 72, 24, ...)
q = 1/3

$a_{n} = a_{1} . q^{(n -1)} \\a_{12} = 216.(\frac{1}{3})^{11} \\\\a_{12} = 216. \frac{1}{177147} : (27) \\a_{12} = 8. \frac{1}{6561} \\ \\a_{12} = \frac{8}{6561}$