Question

calcule as potências:


a) $7^{2}$=


b)$10^{2}$=


c)$2^{1}$=


d) $5^{0}$=


e)$4^{-3}$=


f)$(\frac{2}{3)^{2} }$=


por favor me ajudem !!

Answer 1

a) $7^2=7\cdot7=49$

b) $10^2=10\cdot10=100$

c) $2^1=2$

d) $5^0=1$

e) $4^{-3}=\left(\dfrac{1}{4}\right)^3=\dfrac{1^3}{4^3}=\dfrac{1}{64}$

f) Acredito que a potência seja $\left(\dfrac{2}{3}\right)^2$. Então: $\left(\dfrac{2}{3}\right)^2=\dfrac{2^2}{3^2}=\dfrac{4}{9}$