Question

a area do triangulo cujos os vertices sao os pontos(1,2),(3,5),(4,1)

Answer 1

Resposta:

5,5

Explicação passo a passo:

$\displaystyle det=\left[\begin{array}{ccc}1&2&1\\3&5&1\\4&1&1\end{array}\right] \\\\\\det=1.5.1+2.1.4+3.1.1-4.5.1-3.2.1-1.1.1=5 + 8 + 3-20-6-1=-11$

$\displaystyle Onde~a~\acute{a}rea~(A)\\\\ A=\frac{|det|}{2} =\frac{|-11|}{2}=5,5$