Question

Quais são as raizes da equação: X. (4x-1)=3. (x+1)

Answer 1

Resposta:

x'= 1/2 x"=3/2

Explicação passo a passo:

X. (4x-1)=3. (x+1)

4x²-x=3x+3

4x²-4x-3=0

delta = 64

x'= 1/2 x"=3/2

Answer 2

Resposta:

Explicação passo a passo:

x(4x-1)=3(x+1), aplicando a distributiva

4x² - x = 3x + 3

4x² -3x -x -3 = 0

4x² -4x -3 =0

$\displaystyle Aplicando~a~f\acute{o}rmula~de~Bhaskara~para~4x^{2}-4x-3=0~~e~comparando~com~(a)x^{2}+(b)x+(c)=0,~determinamos~os~coeficientes:~\\a=4{;}~b=-4~e~c=-3\\\\C\acute{a}lculo~do~discriminante~(\Delta):&\\&~\Delta=(b)^{2}-4(a)(c)=(-4)^{2}-4(4)(-3)=16-(-48)=64\\\\C\acute{a}lculo~das~raizes:&\\x^{'}=\frac{-(b)-\sqrt{\Delta}}{2(a)}=\frac{-(-4)-\sqrt{64}}{2(4)}=\frac{4-8}{8}=\frac{-4}{8}=-0,5\\\\x^{''}=\frac{-(b)+\sqrt{\Delta}}{2(a)}=\frac{-(-4)+\sqrt{64}}{2(4)}=\frac{4+8}{8}=\frac{12}{8}=1,5$

$\\\\S=\{-0,5;~1,5\}$