Question

determine a razão da pg onde: a1= 1/3^28 e a10= 1/3^10​

Answer 1

Resposta:

Explicação passo a passo:

an=a1.q^(n-1)

a10=1/3^28.q^(10-1)

1/3^10=1/3^28.q^9

q^9=1/3^10:1/3^28

q^9=1/3^-18

q^9=3^18

q=9V3^18 [ raiz nona de 3 elevado a 9]

q=3^18/9

q=3^2

q=9