Question

A soma dos 6 primeiros termos da PG do (2,12,...);

Answer 1

$> resolucao \\ \\ \geqslant progressao \: \: geometrica \\ \\ q = \frac{a2}{a1} \\ q = \frac{12}{2} \\ q = 6 \\ \\ \\ sn = \frac{a1(q {}^{n} - 1)}{q - 1} \\ \\ sn = \frac{2(6 {}^{6} - 1)}{6 - 1} \\ \\ sn = \frac{2(46656 - 1)}{5} \\ \\ sn = \frac{2 \times 46655}{5} \\ \\ sn = \frac{93310}{5} \\ \\ sn = 18662 \\ \\ \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant \geqslant \geqslant \geqslant$