Question

vou dar 30 pontos
$\frac{1}{3} + \frac{2}{15} - \frac{3}{10} ( \frac{8}{5} + \frac{2}{3} ) = 2 \times$
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Answer 1

Resposta: $x = - 0,106$

Explicação passo a passo:

$\frac{1}{3} +\frac{2}{15} -\frac{3}{10}* (\frac{8}{5} +\frac{2}{3} ) = 2x$

 $\frac{1}{3} +\frac{2}{15} -\frac{3}{10}* \frac{34}{15} = 2x$

$\frac{1}{3} +\frac{2}{15} -\frac{1}{5}* \frac{17}{5} = 2x$

$\frac{1}{3} +\frac{2}{15} - \frac{17}{25} = 2x$

$-\frac{16}{75} = 2x$

$2x = -\frac{16}{75}$

$x = -\frac{8}{75}$

$x = -0,106$

Answer 2

$\LARGE\tt{} \dfrac{1}{3} + \dfrac{2}{15} - \dfrac{3}{10} \times ( \dfrac{8}{5} + \dfrac{2}{3} ) = 2x \\ \\ \LARGE\tt{} \dfrac{1}{3} + \dfrac{2}{15} - \dfrac{3}{10} \times \dfrac{34}{15} = 2x \\ \\ \LARGE\tt{} \dfrac{1}{3} + \dfrac{2}{15} - \dfrac{\cancel{3}}{10} \times \frac{34}{\cancel{15}} = 2x \\ \\ \LARGE\tt{} \dfrac{1}{3} + \dfrac{2}{15} - \dfrac{1}{10} \times \dfrac{34}{5} = 2x \\ \\ \LARGE\tt{} \dfrac{1}{3} + \dfrac{2}{15} - \dfrac{3}{\cancel{10} } \times \dfrac{\cancel{34}}{5} = 2x \\ \\ \LARGE\tt{} \dfrac{1}{3} + \dfrac{2}{15} - \dfrac{1}{5} \times \dfrac{17}{5} = 2x \\ \\ \LARGE\tt{} \dfrac{1}{3} + \dfrac{2}{15} - \dfrac{17}{25} = 2x \\ \\ \LARGE\tt{} - \dfrac{16}{75} = 2x \\ \\ \LARGE\tt{}2x = - \dfrac{16}{75} \\ \\ {\large\boxed{\boxed{  { \LARGE \tt 2x = - \dfrac{16}{75} }}}}$

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