Question

(-5ax).(-x/2)

(a²bc/4).(3a²p)​

Answer 1

Resposta:

( - 5ax ) . ( - x/2) = + 5ax²/2

(a².b.c/4). (3a²p)= 3a^4 .b.c.p/4

obs; basta somar os expoentes com bases iguais, conservando o denominador.

Explicação passo a passo:

Answer 2

Resposta:

A)(-5ax).((-x/2)=5ax^2 /2

B)(a^2 bc/4).(3a^2 p)=3a^3 bcp/4

$a)( - 5ax).( - \frac{x}{2}) \\ ( - 5ax) \times ( - \frac{x}{2}) \\ 5ax \times \frac{x}{2} \\ ( - 5ax) \times ( - \frac{x}{2}) \\ 5ax \times \frac{x}{2} \\ 5ax \times \frac{x}{2}\\ \frac{5ax {}^{2} }{4} \\ ( - 5ax) \times ( - \frac{x}{2}) \\ \frac{5ax {}^{2} }{2} \\ resposta \\ \frac{5ax {}^{2} }{2} \\ \\ b)( \frac{a {}^{2}bc }{4}).(3ap) \\ ( \frac{a {}^{2}bc}{4}) \times (3ap) \\ \frac{a {}^{2}bc }{4} \times 3ap \\ \frac{a {}^{2}bc \times 3ap }{4} \\ \frac{a {}^{2} \times bc \times 3a {}^{1}p }{4} \\ \frac{a {}^{2 + 1}bc \times 3p}{4} \\ \frac{a {}^{3}bc \times 3p}{4} \\ \frac{3a {}^{3}bcp }{4} \\ \frac{a {}^{2}bc}{4} \times 3ap \\ \frac{3a {}^{3}bcp }{4} \\ resposta \\ \frac{3a {}^{3}bcp}{4}$