Question

(1-2a)³ como fazer isso??
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Answer 1

Explicação passo-a-passo:

( 1 - 2a )^3 = ( 1 - 2a ) . (1 - 2a) =

(1 - 2a) (1 - 4a + 4a^2) = 1 - 4a + 4a^2 - 2a + 8a^2 + 8a^3 =

1 - 6a + 12a^2 - 8a^3

Answer 2

Resposta:

$8a {}^{3} + 12a {}^{2} - 6a + 1$

Explicação passo-a-passo:

$(1 - 2a) {}^{3} \\ (1 - 2a) {}^{3} \\ 1 {}^{3} - 3 \times 1 {}^{2} \times 2a + 3 \times 1 \times (2a) {}^{2} - (2a) {}^{3} \\ 1 - 3 \times 1 {}^{2} \times 2a + 3 \times 1 \times (2a) {}^{2} - (2a) {}^{3} \\ 1 {}^{3} - 3 \times 1 {}^{2} \times 2a + 3 \times 1 \times (2a) {}^{2} - (2a) {}^{3} \\ 1 - 3 \times 1 \times 2a + 3 \times 1 \times (2a) {}^{2} - (2a) {}^{3} \\ 1 {}^{3} - 3 \times 1 {}^{2} \times 2a + 3 \times 1 \times (2a) {}^{2} - (2a) {}^{3} \\ 1 - 3 \times 1 \times 2a + 3 \times 1 \times4a {}^{2} - (2a) {}^{3} \\ 1 {}^{3} - 3 \times 1 {}^{2} \times 2a + 3 \times 1 \times (2a) {}^{2} - (2a) {}^{3} \\ 1 - 3 \times 1 \times 2a + 3 \times 1 \times 4a {}^{2} - 8a {}^{3} \\ 1 - 6a + 3 \times 1 \times 4a {}^{2} - 8a {}^{3} \\ 1 - 3 \times 1 \times 2a +3 \times1 \times 4a {}^{2} - 8a {}^{3} \\ 1 - 6a + 12a {}^{2} - 8a {}^{3} \\ (1 - 2a) {}^{3} \\ 1 - 6a + 12a {}^{2} - 8a {}^{3} \\ - 8a {}^{3} + 12a {}^{2} - 6a + 1 \\ resposta \\ - 8a {}^{3} + 12a {}^{2} - 6a + 1$