Question

4) Calcule o 1º termo de uma PG, sabendo que a10 = 2 560 e q = 2.​

Answer 1

$> resolucao \\ \\ \geqslant progressao \: \: geometrica \\ \\ an = a1 \times q {}^{n - 1} \\ 2560 = a1 \times 2 {}^{10 - 1} \\ 2560 = a1 \times 2 {}^{9} \\ 2560 = a1 \times 512 \\ a1 = \frac{2560}{512} \\ a1 = 5 \\ \\ \\ \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant \geqslant$