Question

1. calcule os produtos

a) (x+5).(x²+2)

b) (3x+2).(2x+1)

c) (x+7).(x-4)

d) (3x+4).(2x1)​

Answer 1

$a) \\ (x + 5) \: . \: (x {}^{2} + 2) \\ x \: . \: (x {}^{2} + 2) + 5(x {}^{2} + 2) \\ \boxed{\boxed{\boxed{x {}^{3} + 2x + 5x {}^{2} + 10}}}$

$b) \\ (3x + 2) \: . \: (2x + 1) \\ 3x \: . \: (2x + 1) + 2(2x + 1) \\ 6x {}^{2} + 3x + 4x + 2 \\ \boxed{\boxed{\boxed{6x {}^{2} + 7x + 2 }}}$

$c) \\ (x + 7) \: . \: (x - 4) \\ x \: . \: (x - 4) + 7(x - 4) \\ x {}^{2} - 4x + 7x - 28 \\ \boxed{\boxed{\boxed{x {}^{2} + 3x - 28 }}}$

$d) \\ (3x + 4) \: . \: (2x - 1) \\ 3x \: . \: (2x - 1) + 4(2x - 1) \\ 6x {}^{2} - 3x +8x - 4 \\ \boxed{\boxed{\boxed{6x {}^{2} + 5x - 4}}}$

atte. yrz

Answer 2

Resposta:

a)

$\sf{(x+5).(x²+2)}$

$\sf{x. {x}^{2} + 2x + 5 {x}^{2} + 5x2 }$

$\sf{ {x}^{3} + 2x + 5 {x}^{2} + 5x2 }$

$\rightarrow\boxed{\boxed{\sf{ {x}^{3} + 2x + 5 {x}^{2} + 10 }}}\checkmark$

b)

$\sf{(3x+2).(2x+1)}$

$\sf{3x.2x + 3x + 2x2x + 2}$

$\sf{6 {x}^{2} + 3x + 2x2x + 2 }$

$\sf{6 {x}^{2} + 3x + 4x + 2 }$

$\rightarrow\boxed{\boxed{\sf{6 {x}^{2} + 7x + 2 }}}\checkmark$

c)

$\sf{(x+7).(x-4)}$

$\sf{x.x - 4x + 7x - 7x4}$

$\sf{ {x}^{2} - 4x + 7x - 7x4}$

$\sf{ {x}^{2} - 4x + 7x - 28 }$

$\rightarrow\boxed{\boxed{\sf{ {x}^{2} + 3x - 28 }}}\checkmark$

d)

$\sf{(3x+4).(2x1)}$

$\sf{(3x + 4)x2}$

$\rightarrow\boxed{\boxed{\sf{6x + 8}}}\checkmark$

Explicação passo-a-passo:

(espero ter colaborado)