Question

6) Determine a fração geratriz das seguintes dízimas periódicas composta:
a) 0,71515...
b) 0,0703703...
c) 1,1747474...
d) 3,5818181...
e) 12,4030303...
f) 8,6535353...
g) 5,479999...
h) 4,07595959...

Answer 1

Resposta:

Explicação passo a passo:

a)  0,71515... = 715-7/990 = 708/990

b)  0,0703703... = 0703-0/9990 = 703/9990

c)  1,1747474... = 1 + 174-1/990 = 1 + 173/990 =

1.990+173/990 = 1163/990

d)  3,5818181... = 3 + 581-5/990 = 3 + 576/990 =

3.990+576/990 = 3546/990

e)  12,4030303... = 12 + 403-4/990 = 12 + 399/990 =

12.990+399/990 = 12279/990

f)  8,6535353... = 8 + 653-6/990 = 8 + 647/990 =

8.990+647/990 = 8567/990

g)  5,479999... = 5 + 479-47/900 = 5 + 432/900 =

5.900+432/900 = 4932/900

h)  4,07595959... = 4 + 0759-07/9900 = 4 + 752/9900 =

4.9900+752/9900 = 40352/9900