Question

determine o valor de x, nós intens abaixo:
a)
${x}^{2} = 563$
b)
${x}^{2} = 0.004$

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Answer 1

Resposta passo a passo:

a)

$x^{2} =563\\\\x =\pm\sqrt{563}$

b)

$x^{2} =0.004\\\\x^{2} =4\times10^{-3} \\\\x^{2} =4\times\frac{1}{10^{3} } \\\\x^{2} =\frac{4}{10^{3} } \\\\x^{2} =\frac{2^{2}\times1 }{10^{2}\times10 } \\\\x^{2} =\frac{2^{2} }{10^{2} } \times\frac{1}{10} \\\\x^{2} =(\frac{2}{10} )^{2} \times\frac{1}{10} \\\\x^{2} =(\frac{1}{5} )^{2} \times\frac{1}{10} \\\\x=\pm\sqrt{(\frac{1}{5} )^{2} \times\frac{1}{10}} \\\\x=\pm(\sqrt{(\frac{1}{5} )^{2}} \times\sqrt{\frac{1}{10}}) \\\\x=\pm(\frac{1}{5} \times\frac{\sqrt{1} }{\sqrt{10} })$

$x=\pm(\frac{1}{5} \times\frac{1 }{\sqrt{10} })\\\\x=\pm(\frac{1}{5} \times\frac{1}{\sqrt{10} } \times\frac{\sqrt{10}}{\sqrt{10}}) \\\\x=\pm(\frac{1}{5} \times\frac{1\times\sqrt{10}}{\sqrt{10}\times\sqrt{10}}) \\\\x=\pm(\frac{1}{5} \times\frac{\sqrt{10}}{\sqrt{10}^{2} } )\\\\x=\pm(\frac{1}{5} \times\frac{\sqrt{10}}{10 })\\\\x=\pm\frac{1\times\sqrt{10}}{5\times10}\\\\x=\pm\frac{\sqrt{10}}{50}$