Question

A função f (×) =5×-10, então f (3) + f (4) e:
ajudar por favor!​

Answer 1

Resposta:

$f(x) = 5x - 10$

$f(3) = 5.3 - 10$

$f(3) = 15 - 10$

$f(3) = 5$

$f(x) = 5x - 10$

$f(4) = 5.4 - 10$

$f(4) = 20 - 10$

$f(4) = 10$

Assim temos :

$f(3) + f(4) = 5 + 10 = 15$

Espero ter ajudado.

Bons estudos.

Answer 2

$\mathsf{\purple{Vamos~l\acute{a}!!!}}$

Para resolvermos essa $\mathsf{\green{func_{\!\!\!,} \tilde{a}o}}$ precisamos trocar o número que está dentro do parênteses pela letra "x" e depois calcular.

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EX:

 $\mathsf{f(\green{2})}$ $=$ $\mathsf{5\times\green{2}-10}$

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$\mathtt{\red{Resposta:}}$

15

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$\mathsf{\pink{Explicac_{\!\!\!,}\tilde{a}o:}}$

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$\mathtt{\blue{F(3)}=\red{5}}$

$\boxed{\begin{array}{lr}\mathsf{\green{f(3)=5\times3-10}}\\\\\mathsf{f(3)=15-10}\\\\\mathsf{f(3)=\red{5}}\end{array}}$

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$\mathtt{\blue{F(4)}=\red{10}}$

$\boxed{\begin{array}{lr}\mathsf{\green{f(4)=5\times4-10}}\\\\\mathsf{f(4)=20-10}\\\\\mathsf{f(4)=\red{10}}\end{array}}$

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_________________________

Agora nós somamos o resultado de cada um:

$\green{\mathsf{5+10}}\mathsf{=\red{15}}$

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$\boxed{\mathbf{Ass:\color{lime}\diagup\!\!\!\!T\diagup\!\!\!\!O\diagup\!\!\!\!D\diagup\!\!\!\!D\diagup\!\!\!\!Y}}$

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