Question

Me ajudem por favor, eu não entendi como se faz
$( \frac{3x}{2} + \frac{1y}{2} ) {}^{2}$
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Answer 1

Resposta:

$\frac{9 {x}^{2} + 6xy + {y}^{2} }{4}$

Explicação passo-a-passo:

$( \frac{3x}{2} + \frac{1y}{2} )^{2} \\ \\ ( \frac{3x}{2} + \frac{y}{2} )^{2} \\ \\ ( \frac{3x + y}{2} )^{2} \\ \\ ( \frac{3x + y}{4} )^{2} \\ \\ \frac{9 {x}^{2} + 6xy + {y}^{2} }{4}$

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Answer 2

Explicação passo-a-passo:

$( \frac{3x}{2} + \frac{y}{2} ) {}^{2} = ( \frac{3x + y}{2} ) {}^{2} = \frac{(3x + y) {}^{2} }{2 {}^{2} } = \frac{(3x) {}^{2} + 6xy + y {}^{2} }{4}$

$\frac{9x {}^{2} + 6xy + y {}^{2} }{4}$