Question

Me ajude a resolver as equações prfv . -x²+12x-20=0

Answer 1

Resposta:

Fórmula de Bhaskara

$-x^{2} +12x-20=0\\ \\ coeficientes:\\ a=-1\\ b=12\\ c=-20\\ \\ delta=b^{2} -4.a.c\\ \\ delta=12^{2} -4.(-1).(-20)\\ \\ delta=144-80\\ \\ delta=64$

$x=\frac{-b+-\sqrt{delta} }{2.a} \\ \\ x=\frac{-12+-\sqrt{64} }{2.(-1)} \\ \\ x=\frac{-12+-8}{-2} \\ \\ x'=\frac{-12+8}{-2} =\frac{-4}{-2} =+2\\ \\ x''=\frac{-12-8}{-2} =\frac{-20}{-2} =+10\\ \\ S~~\left \{ {{2,~~10} {}} \}$