Question

[raiz quadrada de 100-(2 elevado a 4-8)*2-24]÷[2 elevado a 3-(-3+2)]+(2-4)(3-5)(10+4)-1​

Answer 1

= [√100 - (2⁴ - 8) . 2 - 24] ÷ [2³ - (- 3 + 2)] + (2 - 4) . (3 - 5) . (10 + 4) - 1

= [10 - (16 - 8) . 2 - 24] ÷ [8 - (- 1)] - 2 . (- 2) . 14 - 1

= [10 - (16 - 8) . 2 - 24] ÷ [8 - (- 1)] + 56 - 1

= [10 - 8 . 2 - 24] ÷ [8 + 1] + 56 - 1

= [10 - 16 - 24] ÷ 9 + 56 - 1

= - 30 ÷ 9 + 56 - 1

≊ - 3,333 + 56 - 1

≊ - 4,333 + 56

≊ - 51,667

atte. yrz

Answer 2

Resposta:

$\sf{segue \: abaixo \: a \: resposta}$

Explicação passo-a-passo:

$\sf{√100-(2^4-8)*2-24]÷[2^3-(-3+2)]+(2-4)(3-5)(10+4)-1}$

$\sf{(10 - ( {2}^{4} - 8)x2 - 24) \div ( {2}^{3} - ( - 3 + 2)) + (2 - 4)x(3 - 5)x(10 + 4) - 1 }$

$\sf{(10 - (16 - 8)x2 - 24) \div ( {2}^{3} - ( - 3 + 2)) + (2 - 4)x(3 - 5)x(10 + 4) - 1}$

$\sf{(10 - (1 6 - 8)x2 - 24) + (8 - ( - 3 + 2)) + (2 - 4)x(3 - 5)x(10 + 4) - 1}$

$\sf{(10 - (16 - 8)x2 - 24) \div (8 - ( - 1)) + (2 - 4)x(3 - 5)x(10 + 4) - 1}$

$\sf{(10 - (16 - 8)x2 - 24) \div (8 - ( - 1)) - 2(3 - 5)x(10 + 4) - 1}$

$\sf{(10 - (16 - 8)x2 - 24) + (8 - ( - 1)) - 2x( - 2)x(10 + 4) - 1}$

$\sf{(10 - (16 - 8)x2 - 24) \div (8 - ( - 1)) - 2x( - 2)x14 - 1}$

$\sf{(10 - 8x2 - 24) \div (8 - ( - 1)) - 2x( - 2)x14 - 1}$

$\sf{(10 - 8x2 - 24) \div (8 + 1) - 2x( - 2)x14 - 1}$

$\sf{(10 - 8 x2 - 24) \div (8 + 1) + 56 - 1}$

$\sf{(10 - 16 - 24) \div (8 + 1) + 56 - 1}$

$\sf{(10 - 16 - 24) \div 9 + 56 - 1}$

$\sf{ - 30 \div 9 + 56 - 1}$

$\sf{ - 30 \div 9 = - \frac{30}{9} }$

$\sf{ - \frac{30}{9} + 56 - 1}$

$\sf{56 - 1 = 55}$

$\sf{ - \frac{30}{9} + 55}$

$\boxed{\boxed{{\sf{\boxed{\boxed{{\sf{ \frac{155}{3} }}}}}}}}$