• Matéria: Matemática
  • Autor: mbaldoino38
  • Perguntado 3 anos atrás

ajuda aí ????????.....

Anexos:

Respostas

respondido por: mlealrj
1

Exercício 5:

a)

2\sqrt{75}+2\sqrt{3}-2\sqrt{12}\\\\2\sqrt{3.5^{2}}+2\sqrt{3}-2\sqrt{2^{2}.3}\\\\2.5\sqrt{3}+2\sqrt{3}-2.2\sqrt{3}\\\\10\sqrt{3}+2\sqrt{3}-4\sqrt{3}\\\\8\sqrt{3}

b)

\sqrt{50}+\sqrt{18}-\sqrt{8}\\\\\sqrt{2.5^{2} }+\sqrt{2.3^{2} }-\sqrt{2^{3}}\\\\5\sqrt{2}+3\sqrt{2}-2\sqrt{2}\\\\6\sqrt{2}

Exercício 6:

\sqrt{75}:\sqrt{3}=\sqrt{75:3}=\sqrt{25}=5

\sqrt{2}.\sqrt{10}=\sqrt{2.10} =\sqrt{20}=\sqrt{2^{2}.5}=2\sqrt{5}

\sqrt[3]{32}:\sqrt[3]{16}=\sqrt[3]{32:16}=\sqrt[3]{2}

\sqrt[3]{3}.\sqrt[3]{9}=\sqrt[3]{3.9}=\sqrt[3]{27}=3

Exercício 7:

a) \sqrt{\sqrt[3]{\sqrt{2}}}=\sqrt[2.3.2]{2}=\sqrt[12]{2}

b) \sqrt[4]{\sqrt{7}}=\sqrt[4.2]{7}=\sqrt[8]{7}

Exercício 8:

\sqrt[3]{12^{3}}=12

\sqrt[5]{121^{5}}=121

\sqrt[7]{17^{7}}=17

Exercício 9:

x\sqrt[3]{x}=\sqrt[3]{x.x^{3}}=\sqrt[3]{x^{4} }

3\sqrt{5}=\sqrt{5.3^{2}}=\sqrt{5.9}=\sqrt{45}

2a\sqrt{a}=\sqrt{a.2^{2}.a^{2}}=\sqrt{4a^{3}}

Exercício 10:

c) \sqrt[9]{512}=\sqrt[9]{2^{9}}=2

d) \sqrt[4]{176}=\sqrt[4]{2^{4}.11 }=2\sqrt[4]{11}

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