Question

alguém me ajuda por favor!​

Answer 1

$3x+2y+2=0\\\\2y=-3x-2\\\\y=\frac{-3x-2}{2}$

Quando x = - 1:

$y=\frac{-3(-1)-2}{2}=\frac{3-2}{2}=\frac{1}{2}$

$A=(-1,\frac{1}{2})$

Quando x = 0:

$y=\frac{-3(0)-2}{2}=\frac{0-2}{2}=-\frac{2}{2}=-1$

$B=(0,-1)$

Quando x = 1:

$y=\frac{-3(1)-2}{2}=\frac{-3-2}{2}=-\frac{5}{2}$

$C=(1,-\frac{5}{2})$

Quando x = 2:

$y=\frac{-3(2)-2}{2}=\frac{-6-2}{2}=-\frac{8}{2}=-4$

$D=(2,-4)$