Question

lim (x2+x+1 - x2-x+1) x→8

Answer 1

Resposta:

2

Explicação passo a passo:

$\lim_{x \to 8} (x^2+x+1-x^2-x+1)= [(8)^2+(8)+1-(8)^2-(8)+1]=(1+1)=2\\\\\therefore \boxed{\lim_{x \to 8}=2}$