Question

URGENTE


Sendo log3 = 0,477 , log 8 = 0,903 e log5 = 0,699 , calcule
A) log 120
B) log 7,2
C) log 4.5 elevado a 30
D) log 12 elevado a 3,6

(Preciso dos cálculos dessas questões , poderiam me ajudar ? )

Answer 1

Resposta:

Explicação passo a passo:

log 8=0,903

log 2³=0,903

3.log 2=0,903

log 2=0,903/3

log 2=0,301

a.

log 120

log 2.2.2.3.5=

log 2 +log2+log2+log3+log5=

0,301+0,301+0,301+0,477+0,699=

2,079

b.

log 10=1

log 7,2=

log 72/10=

log2.2.2.3.3/10=

log2 +log2+log2+log3+log3-log10=

0,301+0,301+0,301+0,477+0,477-1=

1,857-1=

0,857

c.

log 4,5^30=

30. log 4,5=

30. (log 45/10)=

30.(log3.3.5/10)=

30.(log3+log3+log5-log10)=

30.(0,477+0,477+0,699-1)=

30.(1,653-1)=

30.0,653=

19,59

d.

log 12^3,6

3,6. (log 12)=

3,6. (log 3.2.2)=

3,6. (log 3 + log 2+ log2)=

3,6. (0,477+0,301+0,301)=

3,6.(1,079)=

3,8844